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Assume that an alphabet A has a predetermined order; that is, we write the alphabet as a permutation A=(a1,a2,…,ak), where a1<a2<⋯<ak. For instance, the English alphabet is organized as (A,B,…,Z).
Given two strings s and t having the same length n, we say that s precedes t in the lexicographic order (and write s<Lext) if the first symbol s[j] that doesn't match t[j] satisfies sj<tj in A.
Given: A collection of at most 10 symbols defining an ordered alphabet, and a positive integer n (n≤10).
Return: All strings of length n that can be formed from the alphabet, ordered lexicographically (use the standard order of symbols in the English alphabet).
"""
import itertools
with open("hello.fasta", 'r') as f:
string = f.readline().split()
n = int(f.readline().strip())
result = list(itertools.product(string, repeat = n))