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A bug? #365
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I'm thinking
This works, but ends up with an odd type:
but the same is true if |
Interesting. Thus, this is an error in LinearAlgebra. Should I make an issue for this? Recently I fighted with type piracy in DescriptorSystems. I was not able to get rid of it, but enhanced my handling of such cases (e.g., by internally converting the above to [[1] [2]; I], which works). Now I realize, this was not entirely my fault! |
I'd say it is a design choice, where I is always square. What are you
expecting the output to be?
…On Sun, Nov 7, 2021 at 8:02 AM Andreas Varga ***@***.***> wrote:
Interesting. Thus, this is an error in LinearAlgebra. Should I make an
issue for this?
Recently I fighted with type piracy in DescriptorSystems. I was not able
to get rid of it, but enhanced my handling of such cases (e.g., by
internally converting the above to [[1] [2]; I], which works). Now I
realize, this was not entirely my fault!
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Only the square case is implemented in With my handling of type piracy I get:
I would be happy to get the same with |
I see. That makes some sense at first glance.
On Sun, Nov 7, 2021 at 8:35 AM Andreas Varga ***@***.***> wrote:
Only the square case is implemented in LinearAlgebra.UniformScaling at
line #394:
promote_to_arrays_(n::Int, ::Type{Matrix}, J::UniformScaling{T}) where {T}
= copyto!(Matrix{T}(undef, n,n), J)
With my handling of type piracy I get:
julia> using DescriptorSystems
[ Info: Precompiling DescriptorSystems [a81e2ce2-54d1-11eb-2c75-db236b00f339]
julia> [1 2; I]
3×2 Matrix{Int64}:
1 2
1 0
0 1
I would be happy to get the same with LinearAlgebra too.
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Department of Mathematics
College of Staten Island, CUNY
|
Apparently we have to wait for Julia 1.8 to be fixed in LinearAlgebra. Should we close this issue? |
I started some cleaning of my tests for rational transfer functions. The following fails and was commented out for
RationalTransferFunctions
. It seems however, it doesn't work forRationalFunctions
too.The text was updated successfully, but these errors were encountered: