Generic ZodType factory method

[DeLoooping]

I'm new to zod, so please bear with me.

My project makes extensive use of typescript interfaces and some of them are used for communication between frontend and backend, so I want to use zod to make sure the data is valid and also to parse it directly to objects that implement these interfaces.

For most interfaces, I currently create corresponding zod types like this:

interface TestA {
	value: number;
}

const testA: ZodType<TestA> = z.object({
	value: z.number()
});

I declare their type as ZodType<MyInterface> to make sure they match my interface.
This works great as long as the interfaces don't have any generic type parameters.
I tried to create the zod types for generic interfaces through a factory method like this:

interface TestB<T> {
	value: T
}

function testB<T>(valueType: ZodType<T>): ZodType<TestB<T>> {
	return z.object({
		value: valueType
	});
}

But this only gives me type errors:

Type 'ZodObject<{ value: ZodType<T, ZodTypeDef, T>; }, "strip", ZodTypeAny, { [k in keyof addQuestionMarks<baseObjectOutputType<{ value: ZodType<T, ZodTypeDef, T>; }>, any>]: addQuestionMarks<...>[k]; }, { [k_1 in keyof baseObjectInputType<...>]: baseObjectInputType<...>[k_1]; }>' is not assignable to type 'ZodType<TestB, ZodTypeDef, TestB>'.
The types of '_type.value' are incompatible between these types.
Type 'addQuestionMarks<baseObjectOutputType<{ value: ZodType<T, ZodTypeDef, T>; }>, any>["value"] | undefined' is not assignable to type 'T'.
'T' could be instantiated with an arbitrary type which could be unrelated to 'addQuestionMarks<baseObjectOutputType<{ value: ZodType<T, ZodTypeDef, T>; }>, any>["value"] | undefined'

Is there any way to achieve what I want to do?