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Snake & Ladder.cpp
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Snake & Ladder.cpp
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// C++ program to find minimum number of dice throws required to
// reach last cell from first cell of a given snake and ladder
// board
#include<iostream>
#include <queue>
using namespace std;
// An entry in queue used in BFS
struct queueEntry
{
int v; // Vertex number
int dist; // Distance of this vertex from source
};
// This function returns minimum number of dice throws required to
// Reach last cell from 0'th cell in a snake and ladder game.
// move[] is an array of size N where N is no. of cells on board
// If there is no snake or ladder from cell i, then move[i] is -1
// Otherwise move[i] contains cell to which snake or ladder at i
// takes to.
int getMinDiceThrows(int move[], int N)
{
// The graph has N vertices. Mark all the vertices as
// not visited
bool *visited = new bool[N];
for (int i = 0; i < N; i++)
visited[i] = false;
// Create a queue for BFS
queue<queueEntry> q;
// Mark the node 0 as visited and enqueue it.
visited[0] = true;
queueEntry s = {0, 0}; // distance of 0't vertex is also 0
q.push(s); // Enqueue 0'th vertex
// Do a BFS starting from vertex at index 0
queueEntry qe; // A queue entry (qe)
while (!q.empty())
{
qe = q.front();
int v = qe.v; // vertex no. of queue entry
// If front vertex is the destination vertex,
// we are done
if (v == N-1)
break;
// Otherwise dequeue the front vertex and enqueue
// its adjacent vertices (or cell numbers reachable
// through a dice throw)
q.pop();
for (int j=v+1; j<=(v+6) && j<N; ++j)
{
// If this cell is already visited, then ignore
if (!visited[j])
{
// Otherwise calculate its distance and mark it
// as visited
queueEntry a;
a.dist = (qe.dist + 1);
visited[j] = true;
// Check if there a snake or ladder at 'j'
// then tail of snake or top of ladder
// become the adjacent of 'i'
if (move[j] != -1)
a.v = move[j];
else
a.v = j;
q.push(a);
}
}
}
// We reach here when 'qe' has last vertex
// return the distance of vertex in 'qe'
return qe.dist;
}
// Driver program to test methods of graph class
int main()
{
// Let us construct the board given in above diagram
int N = 30;
int moves[N];
for (int i = 0; i<N; i++)
moves[i] = -1;
// Ladders
moves[2] = 21;
moves[4] = 7;
moves[10] = 25;
moves[19] = 28;
// Snakes
moves[26] = 0;
moves[20] = 8;
moves[16] = 3;
moves[18] = 6;
cout << "Min Dice throws required is " << getMinDiceThrows(moves, N);
return 0;
}