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homework_06_spheres_v
A solid metal sphere of radius [a = 2.5 cm] has a net charge [Q_{in} = - 3.0 n C]. The sphere is surrounded by a concentric conducting spherical shell of inner radius [b = 6.0 cm] and outer radius [c = 9.0 cm]. The shell has a net charge [Q_{out} = [+ 2.0 nC]. What is [V_0], the electric potential at the center of the metal sphere, given the potential at infinity is zero?
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Given
- [\vec E( r) = -\frac{ d v}{ d r} \hat r ]
- [ \vec E = k \frac{ Q}{ r^2}]
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Let
- [a = 2.5 cm = .025 m]
- [b = 6.0 cm = .06 m]
- [c = 9.0 cm = .09 m]
- [Q_{in} = - 3.0 n C]
- [Q_{out} = 2 n C]
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[V = -\left( \int\limits_{\infty}^{c}{ \vec E \cdot d \vec l} \int\limits_{c}^{b}{ \vec E \cdot d \vec l} \int\limits_{b}^{a}{ \vec E \cdot d \vec l} \int\limits_{a}^{0}{ \vec E \cdot d \vec l}\right) ]
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[V = -\left( \int\limits_{\infty}^{c}{ \vec E \cdot d \vec l} \int\limits_{b}^{a}{ \vec E \cdot d \vec l}\right)]
- [\int\limits_{c}^{b}{ \vec E \cdot d \vec l} = 0]
- [\int\limits_{a}^{0}{ \vec E \cdot d \vec l} = 0]
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[V = -\left( \int\limits_{\infty}^{c}{ k \frac{ Q_{out}}{ r^2} dr} \int\limits_{b}^{a}{ k \frac{ Q_{in}}{ r^2} dr}\right)]
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Hints
- [V = kQ/r] cannot be used directly here. We need to start with an expression for [V] which is always true.
- Despite the spherical symmetery, since we are interested in the potential inside the charge distribution, we cannot use [V = k \frac{ Q}{ r}].
- Coulomb's law is always true, but the calculation would be difficult for this problem. We can use the spherical symmetry to significantly reduce our work.
- The spherical symmetry of the problem lets us use the result from Gauss' law. [E = k \frac{ Q_{enclosed}}{ r_2}]
- Divid the problem in four seperate regions
- Inside the sphere [r < a]
- Between the sphere and the shell [a < r < b]
- Inside the sphereical shell [b < r < c]
- Outside the spherical shell [r > c]
- Determine the potential at the origin you need to evaluate
- [V = -\left( \int\limits_{\infty}^{c}{ \vec E \cdot d \vec l} \int\limits_{c}^{b}{ \vec E \cdot d \vec l} \int\limits_{b}^{a}{ \vec E \cdot d \vec l} \int\limits_{a}^{0}{ \vec E \cdot d \vec l}\right) ]
- [V = kQ/r] cannot be used directly here. We need to start with an expression for [V] which is always true.
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[V_0 =]